regular expression to match files

Question

I used the following RE:

^file(\d{1,3})(\w*)(?:\.(\d{0,3})(\w*))? 

To match the following

 file1.bla

or

 file1.1

or

 file1.1.bla

but after:

ls "^file(\d{1,3})(\w*)(?:\.(\d{0,3})(\w*))?"

I not see any match of the relevant files why? Yael

Answer 1

Use ls -1 | grep "^file(\\d{1,3})(\\w*)(?:\\.(\\d{0,3})(\\w*))?" ls -1 | grep "^file(\\d{1,3})(\\w*)(?:\\.(\\d{0,3})(\\w*))?" instead. This pipes the output of ls to grep, and grep filters the input (which is piped from ls) with the regexp.

Answer 2

ls only supports simple matching with ? and * and []

if you need to use regex, use find

find . -regex '.*/regularexpression'

Answer 3

您可以使用此处和其他地方描述的外壳文件名遍历（RE的功能不那么强大）

Answer 4

ls -1 | perl -ne 'print if /^file(\\d{1,3})(\\w*)(?:.(\\d{0,3})(\\w*))?/'

(grep -P is supposed to use Perl regexp but on my system it doesn't seem to work. The only way to be sure you're using Perl regular expressions is to use Perl.)