Most used words in text with php

Question

I found the code below on stackoverflow and it works well in finding the most common words in a string. But can I exclude the counting on common words like "a, if, you, have, etc"? Or would I have to remove the elements after counting? How would I do this? Thanks in advance.

<?php

$text = "A very nice to tot to text. Something nice to think about if you're into text.";


$words = str_word_count($text, 1); 

$frequency = array_count_values($words);

arsort($frequency);

echo '<pre>';
print_r($frequency);
echo '</pre>';
?>

Answer 1

This is a function that extract common words from a string. it takes three parameters; string, stop words array and keywords count. you have to get the stop_words from txt file using php function that take txt file into array

$stop_words = file('stop_words.txt', FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES);

$this->extract_common_words( $text, $stop_words)

You can use this file stop_words.txt as your primary stop words file, or create your own file.

function extract_common_words($string, $stop_words, $max_count = 5) {
      $string = preg_replace('/ss+/i', '', $string);
      $string = trim($string); // trim the string
      $string = preg_replace('/[^a-zA-Z -]/', '', $string); // only take alphabet characters, but keep the spaces and dashes too…
      $string = strtolower($string); // make it lowercase

      preg_match_all('/\b.*?\b/i', $string, $match_words);
      $match_words = $match_words[0];

      foreach ( $match_words as $key => $item ) {
          if ( $item == '' || in_array(strtolower($item), $stop_words) || strlen($item) <= 3 ) {
              unset($match_words[$key]);
          }
      }  

      $word_count = str_word_count( implode(" ", $match_words) , 1); 
      $frequency = array_count_values($word_count);
      arsort($frequency);

      //arsort($word_count_arr);
      $keywords = array_slice($frequency, 0, $max_count);
      return $keywords;
}

Answer 2

There's not additional parameters or a native PHP function that you can pass words to exclude. As such, I would just use what you have and ignore a custom set of words returned by str_word_count .

Answer 3

You can do this easily by using array_diff() :

$words = array("if", "you", "do", "this", 'I', 'do', 'that');
$stopwords = array("a", "you", "if");

print_r(array_diff($words, $stopwords));

gives

 Array
(
    [2] => do
    [3] => this
    [4] => I
    [5] => do
    [6] => that
)

But you have to take care of lower and upper case yourself. The easiest way here would be to convert the text to lowercase beforehand.

Answer 4

Here is my solution by using the built-in PHP functions:

most_frequent_words — Find most frequent word(s) appeared in a String

function most_frequent_words($string, $stop_words = [], $limit = 5) {
    $string = strtolower($string); // Make string lowercase

    $words = str_word_count($string, 1); // Returns an array containing all the words found inside the string
    $words = array_diff($words, $stop_words); // Remove black-list words from the array
    $words = array_count_values($words); // Count the number of occurrence

    arsort($words); // Sort based on count

    return array_slice($words, 0, $limit); // Limit the number of words and returns the word array
}

Returns array contains word(s) appeared most frequently in the string.

Parameters :

string - The input string. - 输入字符串。

array (optional) - List of words which are filtered out from the array, Default empty array. （可选） - 从数组中过滤掉的单词列表，默认为空数组。

string (optional) - Limit the number of words returned, Default . （可选） - 限制返回的单词数，默认值为 。