converting a variable name to a string in C++

Question

I'd like to output some data to a file. For example assume I have two vectors of doubles:

vector<double> data1(10);
vector<double> data2(10); 

is there an easy way to output this to a file so that the first row contains the headings 'data1' and 'data2' followed by the actual contents. The function which outputs the data will be passed various different arrays so hardcoding the name of the heading is not possible - ideally I'd like to convert the variable name to some string and then output that string followed by the contents of the vector array. However, I'm not sure how to convert the variable name 'data1' to a string, or indeed if it can easily be done (from reading the forums my guess is it can't) If this is not possible an alternative might be to use an associative container such as map or perhaps more simply a 'pair' container.

pair<vector<double>,string> data1(10,'data1');  

Any suggestions would be welcome!

Answer 1

You can use the preprocessor "stringify" # to do what you want:

#include <stdio.h>

#define PRINTER(name) printer(#name, (name))

void printer(char *name, int value) {
    printf("name: %s\tvalue: %d\n", name, value);
}

int main (int argc, char* argv[]) {
    int foo = 0;
    int bar = 1;

    PRINTER(foo);
    PRINTER(bar);

    return 0;
}


name: foo   value: 0
name: bar   value: 1

(Sorry for printf , I never got the hang of <iostream> . But this should be enough.)

Answer 2

try this:

#define GET_VARIABLE_NAME(Variable) (#Variable)

//in functions

int var=0;    
char* var_name= GET_VARIABLE_NAME(var);

Answer 3

I had the same problem. After a little bit of experimentation I created following macros that convert names of variables, fields, functions, methods and types to strings.

#define MACRO_VARIABLE_TO_STRING(Variable) (void(Variable),#Variable)

#define MACRO_FUNCTION_TO_STRING(Function) (void(&Function),#Function)

#define MACRO_METHOD_TO_STRING(ClassName,Method) (void(&ClassName::Method),#Method)

#define MACRO_TYPE_TO_STRING(Type) (void(sizeof(Type)),#Type)

The code uses comma operator and void conversion to force compiler to check if variable, function, etc. really exists. The nice thing is that it works well with uninitialized variables too. I tested it on both VC and GCC with all pedantic options I found out without any warning messages.

int GetAndPrintValue(const char* VariableName)
{
   std::cout << VariableName << std::endl;
   return 10;
}

int Variable=GetAndPrintValue(MACRO_VARIABLE_TO_STRING(Variable));

I use such code when I write parsers that reads data from input stream and if parsed variable is out of bounds it throws an exception with name of variable that failed my validity checks.

Answer 4

Slightly adapted from @sarnold's answer, for C++:

#define DEBUG(x) std::cout << #x << " = " << x << std::endl;

An example program which uses this:

int main() {
    int foo = 1;
    DEBUG(foo);

    return 0;
}

Answer 5

您可以使用预处理器，有一个 stringify 标记，但它只能从源中获得，不能从函数中获得（您将获得参数名称）。

Answer 6

我原以为显而易见的答案是让执行输出的函数将标题文本作为字符串参数。

Answer 7

For this case I have made nameof() macro. It returns a std::string name of a variable, type or member. It works like nameof() in C#.

For Example:

#include "nameof.h"

std::vector<double> data1(10);
std::string name = nameof(data1); // "data1"

struct Foo1
{
    struct Foo2
    {
        Foo1* foo1;
    };

    Foo1* foo1;
    Foo2 foo2;
};

name = nameof(Foo1::foo1->foo2.foo1); // "foo1"

name = nameof(123); // std::logic_error exception

Answer 8

I had a similar quest. In Qt, I got tired of constantly writing the variable name as a string without autocomplete when writing to qDebug() . After a lot of trial and error with different macros and functions, I found that this macro works great:

#define PRINT(x) ", " << #x << ": " << x

Example usage:

int someVariable = 42;
double anotherVariable = 13.37;
qDebug().nospace() << "Some text" << PRINT(someVariable) << PRINT(anotherVariable);

Output:

Some text, someVariable: 42, anotherVariable: 13.37

I guess this (or something very similar) will work for std::cout as well.

A bit late to the party, but I hope this can help anyone out there!