Can I have a method argument typed “this class”?

Question

I want to have an argument of type "this class" in an interface's method signature, so that any class, for example MyClass , implementing it will have that method with an argument of type MyClass .

public interface MyInterface {
    public thisClass myMethod(thisClass other);
    ...
}

public class MyClass implements MyInterface {
    // has to reference this class in the implementation
    public MyClass myMethod(MyClass other){
        ...
    }
}

Is this possible, or should I just bind the argument with the interface and have each implementation check for it?

Answer 1

public interface MyInterface<T> {
   public T myMethod(T other);
   ...
}

public class MyClass implements MyInterface<MyClass> {
   // has to reference this class in the implementation
   public MyClass myMethod(MyClass other){
      ...
   } 
}

Answer 2

This somewhat enforces that T is the class that implements the interface:

public interface MyInterface<T extends MyInterface<T>> {
   public T myMethod(T other);
   ...
}