I have a python script bundled into a application (I'm on a mac) and have the application set to be able to open .zip files. But when I say "open foo.zip with bar.py" how do I access the file that I have passed to it?
Additional info: Using tkinter.
What's a good way to debug this, as there is no terminal to pass info to?
You should be using sys.argv[1]
task = sys.argv[1].decode('utf-8')
if task == u'uppercase':
pass
elif task == u'openitems':
item_paths = sys.argv[2:]
for itempath in item_paths:
itempath = itempath.decode('utf-8')
如果我没有大错,那就应该将文件名作为第一个参数传递给脚本sys.argv[1]
。
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