“sed” command in bash

Question

Could someone explain this command for me:

cat | sed -e 's,%,$,g' | sudo tee /etc/init.d/dropbox << EOF
   echo "Hello World"
EOF

What does the "sed" command do?

Answer 1

sed is the Stream EDitor . It can do a whole pile of really cool things , but the most common is text replacement.

The s,%,$,g part of the command line is the sed command to execute. The s stands for substitute, the , characters are delimiters (other characters can be used; / , : and @ are popular). The % is the pattern to match (here a literal percent sign) and the $ is the second pattern to match (here a literal dollar sign). The g at the end means to g lobally replace on each line (otherwise it would only update the first match).

Answer 2

Here sed is replacing all occurrences of % with $ in its standard input.

As an example

$ echo 'foo%bar%' | sed -e 's,%,$,g'

will produce "foo$bar$".

Answer 3

它读取Hello World （ cat ），用$替换所有（ g ） %的出现，并且（over）以root身份将其写入/etc/init.d/dropbox 。

Answer 4

sed is a stream editor. I would say try man sed.If you didn't find this man page in your system refer this URL:

http://unixhelp.ed.ac.uk/CGI/man-cgi?sed