如何从包含所有 XSD 内容的大字符串中获取 XmlSchema 对象?
The Read method is static. So better use
XmlSchema schema = XmlSchema.Read(
schemaReader, (sender, args) =>
{
// HANDLE VALIDATION FAILED
});
You can use a StringReader :
string content = ".......";
XmlSchema schema = new XmlSchema();
schema.Read(new StringReader(content), ValidateSchema);
string xsdContent = "...";
string xmlContent = "...";
XmlSchemaSet schema;
XDocument xmlDoc;
using (var ms = new MemoryStream(Encoding.UTF8.GetBytes(xsdContent)))
{
var xsc = XmlSchema.Read(ms, (o, e) =>
{
Error.SetWarning($"XML Schema error: {e.Message}");
});
schema = new XmlSchemaSet();
schema.Add(xsc);
xmlDoc = XDocument.Parse(xmlContent, LoadOptions.SetLineInfo);
}
xmlDoc.Validate(schema, (o, e) =>
{
// handle validation errors
});
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