how to assign a value to a string array?

Question

for example

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char substr[10][20];

int main() {
    substr[0] = "abc";

    printf("%d", substr[0]);
}

of course above is wrong? how to do it? thanks

Answer 1

You can't assign strings like that in C. Instead, use strcpy(substr[0], "abc") . Also, use %s not %d in your printf

Answer 2

I hate giving 'full' answers to homework questions, but the only way to answer your question is to show you the answer to your problem, because it is so basic:

#include <stdio.h>
#include <string.h>

#define MAXLEN 20

char substr[10][MAXLEN];

int main(void) {
        strncpy(substr[0], "abc", MAXLEN);
        puts(substr[0]);
        return 0;
}

Your code (as is) has several faults:

• You are treating substr[0] as a string literal. You can't do that.
• You were using printf formatters incorrectly. %s is for strings
• You don't need to bother printf() to print a string
• You should (in real code) watch out for buffer overflows, hence strncpy()
• If main() doesn't want / need argc and argv , its arguments should be void
• main() should return a value, as its return type is int
• You aren't using anything out of <stdlib.h> , why include it?

I suggest researching string literals, the functions available in <string.h> as well as format specifiers.

Also note, I am not checking the return of strncpy() , which is something you should be doing. That is left as an exercise for the reader.

Answer 3

Hope this helps:

void main(void)
{
    char* string[10];
    string[0] = "Hello";
}

Otherwise I think ya need to copy it by hand or use strcpy or the like to move it from one block of memory to another.