A question about Python script!

Question

m = raw_input("Please enter a date(format:mm/dd/yyyy): ")
def main():
    if '01' in m:
        n = m.replace('01','Janauary')
        print n
    elif '02' in m:
        n = m.replace('02','February')
        print n
    elif '03' in m:
        n = m.replace('03','March')
        print n
    elif '04' in m:
        n = m.replace('04','April')
        print n
    elif '05' in m:
        n = m.replace('05','May')
        print n
    elif '06' in m:
        n = m.replace('06','June')
        print n
    elif '07' in m:
        n = m.replace('07','July')
        print n
    elif '08' in m:
        n = m.replace('08','August')
        print n
    elif '09' in m:
        n = m.replace('09','September')
        print n
    elif '10' in m:
        n = m.replace('10','October')
        print n
    elif '11' in m:
        n = m.replace('11','November')
        print n
    elif '12' in m:
        n = m.replace('12','December')
        print n

main()

for example, this scrpt can output 01/29/1991 to January/29/1991, but I want it output to January,29,1991 How to do it? how to replace the " / " to " , "?

Answer 1

Please don't do it this way; it's already wrong, and can't be fixed without a lot of work. Use datetime.strptime() to turn it into a datetime , and then datetime.strftime() to output it in the correct format.

Answer 2

Take advantage of the datetime module:

m = raw_input('Please enter a date(format:mm/dd/yyyy)')

# First convert to a datetime object
dt = datetime.strptime(m, '%m/%d/%Y')

# Then print it out how you want it
print dt.strftime('%B,%d,%Y')

Answer 3

就像您替换所有其他字符串一样replace('/',',') 。

Answer 4

You might find a dictionary to be helpful here. It would be "simpler." You could try something as follows.

m = raw_input("Please enter a date(format:mm/dd/yyyy): ")
month_dict = {"01" : "January", "02" : "February", "03" : "March", ...}
# then when printing you could do the following
date_list = m.split("/") # This gives you a list like ["01", "21", "2010"]
print(month_dict[date_list[0]] + "," + date_list[1] + "," + date_list[2]

That will basically get you the same thing in 4 lines of code.

Answer 5

I have just rewrite your code more compact:

m = '01/15/2001'
d = {'01' : 'Jan', '02' : 'Feb'}

for key, value in d.items():
   if key in m:
       m = m.replace(key, value)