The XML schema specifies an index of files. Below is an example of how the XML file should look like.
<?xml version="1.0" encoding="utf-8"?>
<fIndex xsi:schemaLocation="http:address fIndex.xsd" xmlns="address" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<f>
<foN>SomeDir</foN>
<fiN>file1.txt</fiN>
</f>
<f>
<foN>SomeDir</foN>
<fiN>file2.txt</fiN>
</f>
</fIndex>
I used xsd to create the classes needed for the XML. Then filled in some sample code to match the example above.
class Program
{
static void Main(string[] args)
{
fileIndexType table = new fileIndexType();
fileIndexTypeF element1 = new fileIndexTypeF();
fileIndexTypeF element2 = new fileIndexTypeF();
element1.fiN = @"C:\SomeDir";
element1.foN = @"file1.txt";
element2.fiN = @"C:\SomeDir";
element2.foN = @"file2.txt";
fileIndexTypeF[] files = new fileIndexTypeF[2] { element1, element2 };
table.f = files;
}
}
How do I create the above XML file?
You need to serialize the objects.
The XmlSerializer
class can be used for this:
XmlSerializer serializer = new XmlSerializer(typeof(fileIndexType));
using(Stream writer = new FileStream(filename, FileMode.Create))
{
serializer.Serialize(writer, table );
writer.Close();
}
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