C++ templates no matching function call

Question

I have a member function of a template class declared as such:

template <class T>
int Data<T>::getPosition(vector<T> stuff, T newStuff, bool ascending)

I call this somewhere with the line

frequencies.insert(frequencies.begin() + getPosition(frequencies, current, ascending),
                       frequencies[i]);

The variables for that line are declared as:

vector<T> temp;
vector<int> frequencies;
int current = frequency.find(words[i])->second;

However, the call to getPosition gives this error:

Data.h|158|error: no matching function for call to 'primitives::Data<double>::getPosition(std::vector<int, std::allocator<int> >&, int&, bool&)'|
Data.h|165|note: candidates are: int primitives::Data<T>::getPosition(std::vector<T, std::allocator<_CharT> >, T, bool) [with T = double]|

What am I doing wrong here?

Answer 1

getPosition takes three arguments of type vector<T> , T and bool . The templated type T in this case is double (as is shown in the error message), and yet you are trying to pass vector<int> and int as the first and second argument, respectively.

Perhaps the parameters for getPosition should not be templated? Depends on what you are trying to achieve - you do have hard-coded int-vectors there, after all.

Answer 2

您的函数原型在Data<t>上进行了模板化，看起来您正在对类型为Data<double>的对象执行此调用，并在可能需要std::vector<double>传递了std::vector<int>和int std::vector<double>和一个double对应于Data对象的初始模板化类型。

Answer 3

vector<T> temp;

T难道不应该是int，double或bool之类的类型吗？