How to unpack a list?

Question

When extracting data from a list this way

line[0:3], line[3][:2], line[3][2:]

I receive an array and two variables after it, as should be expected:

(['a', 'b', 'c'], 'd', 'e')

I need to manipulate the list so the end result is

('a', 'b', 'c', 'd', 'e')

How? Thank you.

PS Yes, I know that I can write down the first element as line[0], line[1], line[2] , but I think that's a pretty awkward solution.

Answer 1

from itertools import chain
print tuple(chain(['a', 'b', 'c'], 'd', 'e'))

Output:

('a', 'b', 'c', 'd','e')

Answer 2

Try this.

line = ['a', 'b', 'c', 'de']
tuple(line[0:3] + [line[3][:1]] + [line[3][1:]])
('a', 'b', 'c', 'd', 'e')

NOTE: I think there is some funny business in your slicing logic. If [2:] returns any characters, [:2] must return 2 characters. Please provide your input line.

Answer 3

Obvious answer: Instead of your first line, do:

line[0:3] + [line[3][:2], line[3][2:]]

That works assuming that line[0:3] is a list. Otherwise, you may need to make some minor adjustments.

Answer 4

This function

def merge(seq):
    merged = []
    for s in seq:
        for x in s:
            merged.append(x)
    return merged 

source: http://www.testingreflections.com/node/view/4930

Answer 5

def is_iterable(i):
    return hasattr(i,'__iter__')

def iterative_flatten(List):
    for item in List:
        if is_iterable(item):
            for sub_item in iterative_flatten(item):
                yield sub_item
        else:
            yield item

def flatten_iterable(to_flatten):
    return tuple(iterative_flatten(to_flatten))

this should work for any level of nesting