Rotate an image around its center in canvas

Question

I'm trying to do my first image animation on canvas. I want the image to rotate but something is not correct in my code. Any ideas? This is all in a jquery document ready:

var canvas = document.getElementById('logobg1');  
    var ctx = canvas.getContext('2d');

    var img = new Image();   // Create new Image object
    img.src = 'images/containerbg.png'; // Set source path // set img src

    img.onload = function(){ // when image loads
        ctx.drawImage(img,0,0);
        setInterval(function() {
            ctx.save();
            ctx.clearRect(-ctx.canvas.width/2, -ctx.canvas.height/2, ctx.canvas.width, ctx.canvas.height);
            ctx.drawImage(img,0,0);
            ctx.translate(ctx.canvas.width/2, ctx.canvas.height/2); // set canvas context to center
            ctx.rotate(Math.PI / 180 * 0.5); // 1/2 a degree
            ctx.restore();
        }, 16);
    }

Answer 1

just change the order of your code, ie,

ctx.rotate(...);

ctx.drawImage(...);

See a working example http://jsbin.com/owuyiq/

$(function () {
    var canvas = document.getElementById('logobg1');
    var ctx = canvas.getContext('2d');
    var img = new Image();

    var ang = 0; //angle
    var fps = 1000 / 25; //number of frames per sec
    img.onload = function () { //on image load do the following stuff
        canvas.width = this.width << 1; //double the canvas width
        canvas.height = this.height << 1; //double the canvas height
        var cache = this; //cache the local copy of image element for future reference
        setInterval(function () {
            ctx.save(); //saves the state of canvas
            ctx.clearRect(0, 0, canvas.width, canvas.height); //clear the canvas
            ctx.translate(cache.width, cache.height); //let's translate
            ctx.rotate(Math.PI / 180 * (ang += 5)); //increment the angle and rotate the image 
            ctx.drawImage(img, -cache.width / 2, -cache.height / 2, cache.width, cache.height); //draw the image ;)
            ctx.restore(); //restore the state of canvas
        }, fps);
    };

    img.src = 'http://i.stack.imgur.com/Z97wf.jpg?s=128'; //img
});

Answer 2

Based in the accepted answer, this example, allows you to use a fixed canvas size (and not in relation to the image size):

  $(function() { var canvas = document.getElementById('logobg1'); var ctx = canvas.getContext('2d'); var img = new Image(); var ang = 0; //angle var fps = 1000 / 25; //number of frames per sec img.onload = function () { //on image load do the following stuff canvas.width = 500; //Any width canvas.height = 500; //Any height var cache = this; //cache the local copy of image element for future reference var iw = cache.width; var ih = cache.height; setInterval(function () { ctx.save(); //saves the state of canvas ctx.clearRect(0, 0, canvas.width, canvas.height); //clear the canvas ctx.translate(canvas.width/2, canvas.height/2); //let's translate ctx.rotate(Math.PI / 180 * (ang += 5)); //increment the angle and rotate the image ctx.translate(-(canvas.width/2), -(canvas.height/2)); //let's translate ctx.drawImage(img, canvas.width/2 - iw/2, canvas.height/2 - ih/2, iw, ih); //draw the image ;) ctx.restore(); //restore the state of canvas }, fps); }; img.src = 'https://lh4.ggpht.com/wKrDLLmmxjfRG2-E-k5L5BUuHWpCOe4lWRF7oVs1Gzdn5e5yvr8fj-ORTlBF43U47yI=w300'; //img }) 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script> <canvas id="logobg1" > test canvas <canvas> 

Working example: jsbin.com/suwovibove/

Note: try removing ctx.save and ctx.restore for a cool spin.

Answer 3

Based on the comments above, but a bit more simple and in vanilla. This one worked for me perfectly. Of course you should use clearRect in order to erase the canvas on each rendering.

 var canvas = document.querySelector('#my-canvas'); var ctx = canvas.getContext('2d') var ang = 0 function rotateAndRenderImg() { var img = document.querySelector('img') ctx.save() var pos = {x: desiredRenderPosX, y: desiredRenderPosY} ctx.translate(pos.x ,pos.y) ctx.rotate(Math.PI / 180 * (ang += 5)) ctx.drawImage(img, -img.width / 2, -img.height / 2, img.width, img.height) ctx.restore() }