putpixel with pyglet

Question

I'm new to pyglet. I'd like to change a pixel from black to white at each on_draw iteration. So after 1000 iterations, there should be exactly 1000 white pixels in the window. However, I'd like to avoid calling 1000 draw operations in on_draw for that. So I'd like to create an image, do an RGB putpixel on the image, and blit the image to the screen. How can I do that? The pyglet documentation, the examples and the source code aren't too helpful on this.

Answer 1

Since no one gave a really good answer to this.
I'll place one here:

import pyglet
from random import randint

width, height = 500, 500
window = pyglet.window.Window(width=width, height=height)
image = pyglet.image.SolidColorImagePattern((255,255,255,255)).create_image(width, height)

data = image.get_image_data().get_data('RGB', width*3)
new_image = b''

for i in range(0, len(data), 3):
    pixel = bytes([randint(0,255)]) + bytes([randint(0,255)]) + bytes([randint(0,255)])
    new_image += pixel

image.set_data('RGB', width*3, new_image)

@window.event
def on_draw():
    window.clear()
    image.blit(0, 0)

pyglet.app.run()

Essentially, what this does is it creates a white image, that in itself can be drawn in the window. But seeing as we want to do putpixel , i've modified every pixel in the white image as a demo.

Can be used in junction with:

• https://pythonhosted.org/pyglet/api/pyglet.image.ImageData-class.html#get_region

Which can be used to optemize the image manipulation further.

Answer 2

This is too late to help you, but there are ways to do this. For example, blit_into, which modifies a loaded image:

import pyglet
window = pyglet.window.Window(600, 600)
background = pyglet.resource.image('my600x600blackbackground.bmp')
pix = pyglet.resource.image('singlewhitepixel.bmp').get_image_data()

def update(dt):
    background.blit_into(pix, x, y, 0) #specify x and y however you want

@window.event
def on_draw():
    window.clear()
    background.blit(0,0)

pyglet.clock.schedule(update, 1.0/30) #30 frames per second
pyglet.app.run()

Answer 3

It seems there is no easy way to do this in pyglet. So I've given up on using pyglet.