Objective-C Float Rounding

Question

How might I round a float to the nearest integer in Objective-C:

Example:

float f = 45.698f;
int rounded = _______;
NSLog(@"the rounded float is %i",rounded);

should print "the rounded float is 46"

Answer 1

Use the C standard function family round() . roundf() for float , round() for double , and roundl() for long double . You can then cast the result to the integer type of your choice.

Answer 2

The recommended way is in this answer: https://stackoverflow.com/a/4702539/308315

---

Original answer:

cast it to an int after adding 0.5.

So

NSLog (@"the rounded float is %i", (int) (f + 0.5));

Edit: the way you asked for:

int rounded = (f + 0.5);


NSLog (@"the rounded float is %i", rounded);

Answer 3

The easiest way to round a float in objective-c is lroundf :

float yourFloat = 3.14;
int roundedFloat = lroundf(yourFloat); 
NSLog(@"%d",roundedFloat);

Answer 4

For round float to nearest integer use roundf()

roundf(3.2) // 3
roundf(3.6) // 4

You can also use ceil() function for always get upper value from float .

ceil(3.2) // 4
ceil(3.6) // 4

And for lowest value floor()

floorf(3.2) //3
floorf(3.6) //3

Answer 5

如果你想要整数下面的圆形浮点数值是在目标C中舍入浮点值的简单方法。

int roundedValue = roundf(Your float value);

Answer 6

查看rint()的手册页

Answer 7

let's do tried and checkout

//Your Number to Round (can be predefined or whatever you need it to be)
float numberToRound = 1.12345;
float min = ([ [[NSString alloc]initWithFormat:@"%.0f",numberToRound] floatValue]);
float max = min + 1;
float maxdif = max - numberToRound;
if (maxdif > .5) {
    numberToRound = min;
}else{
    numberToRound = max;
}
//numberToRound will now equal it's closest whole number (in this case, it's 1)