“java.lang.UnsupportedOperationException: Not supported yet.”

Question

What I am trying to do :

I am trying to connect to Web Portal [that uses https]using Java. I have written code for supplying user credentials using Authenticator class.When I run the program I get an Exception:

"java.lang.UnsupportedOperationException: Not supported yet"

I have the code posted :

public class Main {

    public class MyAuthenticator extends Authenticator {

        protected PasswordAuthentication getpasswordAuthentication() {
            String username = "username";
            String password = "password";
            // Return the information
            return new PasswordAuthentication(username, password.toCharArray());
        }

        @Override
        public Result authenticate(HttpExchange he) {
            throw new UnsupportedOperationException("Not supported yet.");
        }
    }

    public static void main(String[] args) {
        // TODO code application logic here


        TrustManager[] trustClients = new TrustManager[]{
            new X509TrustManager() {

                public void checkClientTrusted(X509Certificate[] xcs, String string) throws CertificateException {
                    throw new UnsupportedOperationException("Not supported yet.");
                }

                public void checkServerTrusted(X509Certificate[] xcs, String string) throws CertificateException {

                    throw new UnsupportedOperationException("Not supported yet.");
                }

                public X509Certificate[] getAcceptedIssuers() {
                    return null;
                    //throw new UnsupportedOperationException("Not supported yet.");
                }
            }
        };
        try {
            SSLContext sslcontext = SSLContext.getInstance("SSL");
            sslcontext.init(null, trustClients, new java.security.SecureRandom());
            HttpsURLConnection.setDefaultSSLSocketFactory(sslcontext.getSocketFactory());

        } catch (Exception e) {
            System.out.println("in 1st catch " + e);
        }


        try {
            URL url = new URL("https://someURL.server.com/fmk/jsp/ltpaLogin.jsp");
            URLConnection urlconnection = url.openConnection();
            System.out.println(urlconnection);
            System.out.print(urlconnection.getInputStream().toString());



} catch (Exception e) {
            System.out.println("in 2ndcatch " + e.getMessage());
        }
    }
}

the exception "java.lang.UnsupportedOperationException: Not supported yet"is raised in the 2nd Try.Is my approach correct ? if not is there any alternative to do so ?

When I open the page in web browser I get the login page;Once I supply my credentials the web portal is displayed

Can any one please suggest how to hit the webportal and supply my credentials and check the authentication is success or not ? Any sample code snippets will be really helpful Thanks in advance..

Answer 1

Have you seen this code fragment ?

    @Override
    public Result authenticate(HttpExchange he) {
        throw new UnsupportedOperationException("Not supported yet.");
    }

It's precisely the one that will throw the aforementionned exception each time you try to authenticate.

So, to my mind, the solution to your authentication problem is quite simple : implement this method.

Answer 2

if you don't want implement this method :

    @Override
    public Result authenticate(HttpExchange he) {
        throw new UnsupportedOperationException("Not supported yet.");
    }

take it easy , only delete this line of method :

throw new UnsupportedOperationException("Not supported yet.");

Answer 3

You've probably used an IDE such as Netbeans to implement an interface / override an abstract class that needs certain methods implementing. When IDEs do this (Netbeans definitely does) they generate method stubs for you like this so the code still compiles but if you try and call a method you haven't actually implemented you get an unavoidable error.

Usually this means you have to implement the given method, but sometimes an implementation does genuinely call for a blank method stub, in which case just delete the line that's throwing the exception.

Answer 4

This happens when you did not provide implementations for all methods from the interface you've implemented. Check which method you not implemented.

Answer 5

You don't give a body to your method. Check the line where you have the problem and override your method with the code you want.