Ok
I know that this is trivial question but: How can i remove lines from files that are between two known patterns/words:
pattern1
garbage
pattern2
to obtain:
pattern1
pattern2
And does anyone known good(simple written!) resources for studying sed?? With many clear examples?
sed -n '/pattern1/{p; :a; N; /pattern2/!ba; s/.*\n//}; p' inputfile
Explanation:
/pattern1/{ # if pattern1 is found
p # print it
:a # loop
N # and accumulate lines
/pattern2/!ba # until pattern2 is found
s/.*\n// # delete the part before pattern2
}
p # print the line (it's either pattern2 or it's outside the block)
Edit:
Some versions of sed
have to be spoon-fed:
sed -n -e '/pattern1/{' -e 'p' -e ':a' -e 'N' -e '/pattern2/!ba' -e 's/.*\n//' -e '}' -e 'p' inputfile
这可能对你有用:
sed '/pattern1/,/pattern2/{//!d}' file
awk '/pattern1/{g=1;next}/pattern2/{g=0;next}g' file
这个sed代码也可以运行:
sed '/PATTERN1/,/PATTERN2/d' FILE
You may also use the Unix text editor ed:
echo '
pattern1
garbage
pattern2
' > test.txt
cat <<-'EOF' | sed -e 's/^ *//' -e 's/ *$//' | ed -s test.txt &>/dev/null
H
/pattern1/+1,/pattern2/-1d
wq
EOF
For more information see: Editing files with the ed text editor from scripts
for me "sed '\/PATTERN1\/,\/PATTERN2\/d' FILE" is working (between PATTERN1 and last occurrence of PATTERN2)
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