c++ operator overload

Question

//#include <string>
#include <iostream>
#include <string.h>
#include <stdio.h>
using namespace std;

template<class T, class X> class Obj{
T my_t;
X my_x;
public:
    Obj(T t, X x):my_t(t),my_x(x){}
     operator T() const {return my_t;}
};
int main()
{
    int iT;
    Obj<int, float> O(15,10.375);

    iT = O;
    cout << iT << endl;
    return O;
}

about this line : operator T() const {return my_t;} is this operator overload? but I am not so understand which operator is been overloaded? anybody can explain it for me? thanks!

Answer 1

Yes, that is operator overloading. The operator that has been overloaded is the casting operator to type T . That's the operator that is invoked when you ask the compiler to convert an Obj<T,X> into a T .