I'm trying to get some data from my database, and then pass it into an array for later use. I am using MySQLi for my driver.
Here's my code:
// Build a query to get skins from the database
$stmt = $mysqli->prepare('SELECT id, name, description, author, timestamp, url, preview_filename FROM `skins` LIMIT 0, 5');
$stmt->execute();
$stmt->bind_result($result['id'], $result['name'], $result['desc'], $result['auth'], $result['time'], $result['url'], $result['preview']);
// The skins array holds all the skins on the current page, to be passed to index.html
$skins = array();
$i = 0;
while($stmt->fetch())
{
$skins[$i] = $result;
$i++;
}
print_r($skins);
The problem is, when this executes, the $skins
array contains the last result row from the query. This is the print_r of $skins:
Array
(
[0] => Array
(
[id] => 3
[name] => sdfbjh
[desc] => isdbf
[auth] => dfdf
[time] => 1299970810
[url] => http://imgur.com/XyYxs.png
[preview] => 011e5.png
)
[1] => Array
(
[id] => 3
[name] => sdfbjh
[desc] => isdbf
[auth] => dfdf
[time] => 1299970810
[url] => http://imgur.com/XyYxs.png
[preview] => 011e5.png
)
[2] => Array
(
[id] => 3
[name] => sdfbjh
[desc] => isdbf
[auth] => dfdf
[time] => 1299970810
[url] => http://imgur.com/XyYxs.png
[preview] => 011e5.png
)
)
As you can see, the last result from the query is populating all of the array entries for some reason.
Can anyone explain this behaviour and tell me what I'm doing wrong? Thanks. :)
EDIT: Here's the solution:
while($stmt->fetch())
{
foreach($result as $key=>$value)
{
$tmp[$key] = $value;
}
$skins[$i] = $tmp;
$i++;
}
Quoting the (now) first note on the mysqli::fetch
manual page, emphasis mine :
the problem is that the $row
returned is reference and not data .
So, when you write $array[] = $row
, the $array
will be filled up with the last element of the dataset.
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