This is a sequel question (on a different topic) to an earlier question . The code below incorporates Dehstil's suggestion to use specialization.
How should a function that has template template parameters be specialized?
The code below (in which the two specialization lines do not compile) make the question concrete.
#include <cassert>
template<typename S> struct PA1 {};
template<typename S> struct PA2 {};
template<typename S> struct PB {};
template<typename S> struct PC {};
template<typename S> struct A1 { typedef PA1<S> P; };
template<typename S> struct A2 { typedef PA2<S> P; };
template<typename S> struct B { typedef PB <S> P; };
template<typename S> struct C { typedef PC <S> P; };
template<typename S, template<typename> class T> char fn(typename T<S>::P);
template<typename S, template<typename> class T> char fn(typename T<S>::P)
{
return 'a';
}
template<typename S> char fn<B<S> >(B<S>::P) { return 'b'; }
template<typename S> char fn<C<S> >(C<S>::P) { return 'c'; }
int main()
{
PA1<int> pa1;
PA2<int> pa2;
PB<int> pb;
PC<int> pc;
assert( (fn<int, A1>(pa1)) == 'a' );
assert( (fn<int, A2>(pa2)) == 'a' );
assert( (fn<int, B>(pb)) == 'b' );
assert( (fn<int, C>(pc)) == 'c' );
}
It's important for the four function calls fn<...,...>() to have identical signatures when called since they will themselves reside in a template class that applies to the four classes A1/A2/B/C.
Partial Specialization of function template is NOT allowed by the C++ Standard!
Overload your functions instead of specializing them.
Read the explanation as to Why Not Specialize Function Templates? by Herb Sutter
Then read why to overload than specialize : Template Specialization and Overloading by Herb Sutter
Write a class template call
and specialize them as:
template<class S, template<typename> class T>
struct call
{
static char fn(typename T<S>::P &p)
{
return ::fn<S,T>(p);
}
};
template<class S>
struct call<S,B>
{
static char fn(typename B<S>::P &p)
{
return ::fn<S>(p);
}
};
template<class S>
struct call<S,C>
{
static char fn(typename C<S>::P &p)
{
return ::fn<S>(p);
}
};
Then you can use this class template to call all the functions uniformly as:
assert( (call<int, A1>::fn(pa1)) == 'a' );
assert( (call<int, A2>::fn(pa2)) == 'a' );
assert( (call<int, B>::fn(pb)) == 'b' );
assert( (call<int, C>::fn(pc)) == 'c' );
See the online demo : http://www.ideone.com/TISIT
Note also the overloaded function templates in the complete solution at ideone.com (above link)
Functions can be only fully specialized. Use function overloading:
template<typename S> char fn(typename B<S>::P) { return 'b'; }
template<typename S> char fn(typename C<S>::P) { return 'c'; }
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