C++11 char16_t strlen-equivalent function

Question

I have a simple question: Is there a way to do a strlen() -like count of characters in zero-terminated char16_t array?

Answer 1

use

char_traits<char16_t>::length(your_pointer)

see 21.2.3.2 struct char_traits<char16_t> and table 62 of the C++11-Std.

Answer 2

Use pointers:), create a duplicate pointer to the start, then loop through it while (*endptr++); , then the length is given by endptr - startptr . You can actually template this, however, its possible the the compile won't generate the same intrinsic code it does for strlen (for different sizes ofc).

Answer 3

Necrolis answer includes the NULL byte in the length, which probably is not what you want. strlen() does not include the NULL byte in the length.

Adapting their answer:

static size_t char16len(uint16_t *startptr)
{
        uint16_t *endptr = startptr;
        while (*endptr) {
                endptr++;
        }
        return endptr - startptr;
}

I realize there is an accepted C++ answer, but this answer is useful for anyone who stumbles on this post using C (like I did).