I'm trying to programmatically replace <?
with <?php
in a bunch of file, but my sed regex isn't behaving like I expected. Can you tell me what's wrong with it?
I'm testing it on the command line here:
$ sed -e 's/<\?/<\?php/g'
<?
<?php?<?php
d
<?phpd<?php
我不认为你需要逃脱吗?:
sed -e 's/<?/<?php/g'
You don't need to escape the back reference in the replacement.
sed 's#<\?#<?php#'
In a pipe, to correct for doubling the php:
sed 's#<\?#<?php#g' | sed 's#phpphp#php#g'
这也将跳过与<?=$variable
匹配:
sed -e 's/<?\([^=p]\)/<?php\1/g' -e 's/<?$/<?php/g'
Do you really have to use sed, or can you use perl as well?
perl -pi.tmp -e 's,^<\?(?!php),<?php,' *.php *.inc
rm *.tmp
I am using a negative look-ahead to avoid generating <?phpphp
in cases where the files already start with the correct characters.
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