Return value from PHP function

Question

what is wrong with the following code? Hope you understand what I'm trying to do. I'm not very familiar with functions.

function test ($variable) {
   $one = 3;
   if ($variable == 10) {
       $one = "2";
   }
   return $one;
}

foreach ($array as $arraypart) { 
   $part = explode(',',$arraypart);
   test($part[0]);
   echo $one;
}

Answer 1

You need to assign the result of function to a variable:

$one = test($part[0]);

Answer 2

here what happens, your function is being called but no variable is there to catch what test() is returning....

you need catch value which is returned by temp func like this

$val = temp($part[0]); or you can write direct echo temp($part[0]);