Bitwise “~” Operator in C#

Question

Consider this unit test code:

    [TestMethod]
    public void RunNotTest()
    {

        // 10101100 = 128 + 32 + 8 + 4 = 172
        byte b = 172;

        // 01010011 = 64 + 16 + 2 + 1 = 83
        Assert.AreEqual(83, (byte)~b);
    }

This test passes. However without the byte cast it fails because the "~" operator returns a value of -173. Why is this?

Answer 1

A promotion to int occurs on byte because binary complement is not defined for them.

See Unary numeric promotions and Bitwise complement operator .

Intrinsically, when you call ~ on the unsigned 8 bit value 10101100 , it is promoted to the 32-bit signed value 0...010101100 . Its complement is the 32-bit value 1...101010011 , which is equal to -173 for int . A cast of this result into byte is a demotion to the unsigned 8-bit value 01010011 , losing the most significant 24 bits. The end result is interpreted as 83 in an unsigned representation.

Answer 2

Because ~ returns an int. See ~ Operator (C# Reference) (MSDN)

It is only predefined for int, uint, long, and ulong - so there is an implicit cast when using it on byte .