PHP OOP Mysql Query

Question

I'm quite new to PHP OOP and I have a question regarding a simple MYSQL query. I have an index.php page where I want to output my results from my query.class file.

Here is my method,

 public function Query($rowName) {

   $q = mysql_query("SELECT * from p_tuts");

   while($row = mysql_fetch_array($q)) {

       echo $row[$rowName];
   }
 }

Now this works fine and I can call it though my index.php file

$Database->Query('tut_content');

But my issue is I want to wrap each content block in DIV containers and don't want to have to echo the HTML code in the class file, so I want to really echo the row's data in the index file, but unsure how to do this.

Kind regards

Answer 1

Pass the rows back as an array.

public function Query($colName) {

    $q = mysql_query("SELECT * from p_tuts");
    $rows = array();
    while($row = mysql_fetch_assoc($q)) {
        $rows[] = $row[$colName];
    }
    return $rows;
}

It's better this way anyway, because it keeps database code away from output code (ie echo ).

Then output it like so:

<?php
$results = $Database->Query('tut_content');
foreach ($results as $result): ?>
    <div><?php echo $result; ?></div>
<?php endforeach; ?>

Answer 2

You dont want to be doing the echo in your class.

You want to return the row...

This way

 $Database->Query('tut_content'); 

Can be wrapped in the DIV / whatever you need...

Answer 3

OOP functions are the same as normal function. The function as you have it only echos $row[$rowname] . You either want to modify it to have it echo <div>$row[$rowname]</div> or have it return the row values as an array:

while($row = mysql_fetch_array($q)) {
   $output[] = $row[$rowName];
}
return $output;

Answer 4

use the MVC pattern.

http://php-html.net/tutorials/model-view-controller-in-php/

the database belongs to the Model

Good Luck

Answer 5

Or you can use my favorite database layer http://dibiphp.com/ . It's small but smart :-)