I've created a small program wich can read a.txt file.
This file contains a link to another file in this format new_file.txt
The goal is to return the path of the new file, so basically I'm doing this:
String newFileName = getFileName();
int index = oldFilePath.lastIndexOf('\\');
String path = oldFilePath.substring(0, index + 1);
String newFilePath = path + newFileName;
return newFilePath;
For example:
The first file I opened is: C:\a\b\c\oldFile.txt
In this file I found newFile.txt
So the new path will be: C:\a\b\c\newFile.txt
Nice, but what If I find something like this:
..\
or .\.\
or ...
Is there any way to automate this mess?
Thanks
In C#/.Net you have the rather cool Path class .
You can use Path.GetFullPath( string pathname ) to resolve paths eg with \..\
etc in them.
Use Path.GetDirectory()
, Path.GetFileName()
, Path.GetFileNameWithoutExtension()
& Path.GetExtension()
to pull names apart and Path.Combine()
to put them back together again.
You've tagged this as java as well as c#
In java look at FileNameUtils http://commons.apache.org/io/apidocs/org/apache/commons/io/FilenameUtils.html
The normalize method should help
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