for i in $(some function); do somefunction2 $i; done
-su: 0 5 : syntax error in expression (error token is "5 ")
My problem is some function return "0 9" I can't use this:
for i in "0 5"; do somefunction2 $i; done
Results are the same
-su: 0 5 : syntax error in expression (error token is "5 ")
but if use this:
for i in 0 5; do somefunction2 $i; done
It works. Some function for loop and echo this
echo -n "$i "
I want return 0 5
not "0 5"
How can I do?
This should solve your problem:
eval for i in $(some function); do somefunction2 \$i; done
However, it's not clear from your question where does the su
come from?
You don't need to delete anything:
function five {
echo 0;
echo 5;
}
function fiveString {
echo "0 5";
}
for i in `five`;do
echo process $i;
done
for i in $(echo $(fiveString));do
echo process $i;
done
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