As the title suggests I need a way to match more than one zero at the end of a number $
.
100 //match
10 // no match
4000 // match
340 // no match
74003 //no match
I'm using php if that matters.
Attempts: 0+(?!(0))$
0[0-9]+$
$regex = "/0{2,}$/";
var_dump(preg_match($regex, "4000"));
php> $regex = "/0{2,}$/"
php> preg_match($regex, "100")
php> echo preg_match($regex, "100")
1
php> echo preg_match($regex, "10")
0
php> echo preg_match($regex, "4000")
1
php> echo preg_match($regex, "340")
0
php> echo preg_match($regex, "74003")
0
php>
If the number must start with a non-zero:
/^[1-9]+00+$/
If the number can start with a zero:
/^\d*00+$/
if you only want to check if 2 last digits are 0 you may use
if($number % 100 == 0){
//0 will be here too, if you need not it try to add (and $number!=0)
}
regexp will be bit overkill here
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