How to get list of lists in R with my data

Question

here is the function which is working fine, but giving the output in an output which I don't want.

frequencies <- {}

for (k in (1:4))
{   
    interval <- (t(max_period_set[k]))

    intervals <- round(quantile(interval,c(0,0.05,0.15,0.25,0.35,0.45,0.55,0.65,0.75,0.85,0.95,1.0)))
    frequency <- {}
    for (i in (2:length(intervals)))
    {       
        count = 0;      
        for (r in (1:length(interval)))
        {
            if (r == length(interval))
            {
                if (interval[r] >= intervals[i-1] && interval[r] <= intervals[i])
                {
                    count = count + 1
                }
            }
            else
            { 
                if (interval[r] >= intervals[i-1] && interval[r] < intervals[i])
                {
                    count = count + 1
                }
            }
        }   
        frequency <- c(frequency,count)
    }
    frequencies[[length(frequencies)+1]] <- frequency
}

The output is as follows:

> frequencies
[[1]]
 [1] 2 6 5 4 5 4 6 5 5 5 3

[[2]]
 [1] 1 7 5 4 5 4 5 6 5 5 3

[[3]]
 [1] 3 5 5 4 5 4 6 5 5 5 3

[[4]]
 [1] 3 5 5 4 4 6 5 5 5 5 3

I would like to have it in a format as follows:

[[],[],[],[]] which is a list of list whose first element I can access like frequencies[1] to get the first list, etc...

If it is not possible, how can I access the first list values in my current format? frequencies[1] does not give me the first list values back.

Thanks for your help!

Guys an another question:

now I can access the data but r is representing the last line in different format:

[[1]]
 [1] 1.00 0.96 0.84 0.74 0.66 0.56 0.48 0.36 0.26 0.16 0.06 0.00

[[2]]
 [1] 1.00 0.98 0.84 0.74 0.66 0.56 0.48 0.38 0.26 0.16 0.06 0.00

[[3]]
 [1] 1.00 0.94 0.84 0.74 0.66 0.56 0.48 0.36 0.26 0.16 0.06 0.00

[[4]]
 [1] 1.000000e+00 9.400000e-01 8.400000e-01 7.400000e-01 6.600000e-01 5.800000e-01 4.600000e-01 3.600000e-01 2.600000e-01 1.600000e-01 6.000000e-02 1.110223e-16

Why is it happening with the accuracy? the first three lines are as it should be but the last line is odd, the numbers were not infractional numbers, so it can be represented as a number with its accuracy of 2 after comma digits.

Answer 1

frequencies is a list, so you need

 frequencies[[1]]

to access the first element. If list were named, you could also index by element name.

Lists are the most general data structure, and the only one that can

• be nested: lists within lists within ...
• be ragged: does not require rectangular dimensions

so you should try to overcome initial aversion to the fact that it is different. These are very powerful data structures, and are use a lot behind the scenes.

Edit: Also, a number of base functions as well as add-on packages can post-process lists. It starts with something basic like do.call() , goes to lapply and ends all the over at the plyr packages. Keep reading -- there are many ways to skin the same cat, some better than others.

Answer 2

虽然我完全同意Dirk关于列表的用处，但如果所有列表的长度相同，则可以使用as.data.frame()将它们转换为数据帧，然后您可以按列i frequencies[,i]它们进行索引frequencies[,i]或行j frequencies[j,]