Prevent printing key indexes while printing the value - PHP

Question

Hi I have an array like this:

array(
  'Home' => array(
    'About',
    'Contact'
  ),
  'News'
);

I wrote this to printing them:

function show($arr){
    foreach($arr as $key => $value){
      echo "\n<ul>\n<li>\n" . $key;
      if( ! empty($value)){
        if(is_array($value)){
          show($value);
        }else{
          echo $value;
        }
      }
      echo "\n</li>\n</ul>\n";
    }
}

My problem is when I try to echo $value It'll print something like this:

Home
  0About
  1Contact
0News

I tried to echo $key where the echo $value is here now and I understood it's the key index which is gonna write before the News field or any field that is not an array. I fixed it with turning the single fields to this:

array(
  'Home' => array(
    'About' => **array()**,
    'Contact' => **array()**
  ),
  'News' => **array()**
);

But I don't want to define additional empty arrays!

Peace Out!

Answer 1

 function show($arr){
     foreach($arr as $key => $value){
       echo "\n<ul>\n<li>"; 
       if( ! empty($value)){
         if(is_array($value)){
          echo '\n'.$key;
           show($value);
         }else{
           echo $value;
         }
       }
       echo "\n</li>\n</ul>\n";
     } }

I would say you have to change the place of you echo (of the $key). If it's not an array, you don't care about the key, right ?

Answer 2

function show($arr){
foreach($arr as $key => $value){
  if (is_numeric($key))
  echo "\n<ul>\n<li>\n";
  else
  echo "\n<ul>\n<li>\n" . $key;
  if( ! empty($value)){
    if(is_array($value)){
      show($value);
    }else{
      echo $value;
    }
  }
  echo "\n</li>\n</ul>\n";
}
}

I guess is_numeric should solve your problem.