I want to display the last 10 lines of my log file, starting with the last line - like a normal log reader. I thought this would be a variation of the tail command, but I can't find this anywhere.
GNU (Linux) uses the following :
tail -n 10 <logfile> | tac
tail -n 10 <logfile>
prints out the last 10 lines of the log file and tac
(cat spelled backwards) reverses the order.
BSD (OS X) of tail
uses the -r
option:
tail -r -n 10 <logfile>
For both cases , you can try the following:
if hash tac 2>/dev/null; then tail -n 10 <logfile> | tac; else tail -n 10 -r <logfile>; fi
NOTE: The GNU manual states that the BSD -r
option "can only reverse files that are at most as large as its buffer, which is typically 32 KiB" and that tac
is more reliable. If buffer size is a problem and you cannot use tac
, you may want to consider using @ata's answer which writes the functionality in bash.
tac
does what you want. It's the reverse of cat
.
tail -10 logfile | tac
我最终使用tail -r
,它在我的OSX上工作( tac
没有)
tail -r -n10
这是以相反顺序打印输出的完美方法
tail -n 10 <logfile> | tac
You can do that with pure bash:
#!/bin/bash
readarray file
lines=$(( ${#file[@]} - 1 ))
for (( line=$lines, i=${1:-$lines}; (( line >= 0 && i > 0 )); line--, i-- )); do
echo -ne "${file[$line]}"
done
./tailtac 10 < somefile
./tailtac -10 < somefile
./tailtac 100000 < somefile
./tailtac < somefile
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