I have an array of hashed names and emails, like this:
array = [{"email"=>"test@test.com", "name"=>"Test"},
{"email"=>"testA@gmail.com", "name"=>"Test A"},
{"name"=>"Test B", "email"=>"testB@test.com"},
{"email"=>"testC@yahoo.com", "name"=>"Test C"},
{"name"=>"Test D", "email"=>"testD@hotmail.com"},
{"email"=>"testE@test.com"},
{"name"=>"Test F", "email"=>"testF@test.com"}]
I want to filter out certain emails in a "blacklist" array. The following works, but it's too verbose.
blacklist = ["@test.com", "@gmail.com"]
na = array
blacklist.each do |b|
na = na.reject{ |e| e["email"].include?(b) }
end
# na => [{"email"=>"testC@yahoo.com", "name"=>"Test C"}, {"name"=>"Test D", "email"=>"testD@hotmail.com"}]
Can someone help me by putting this into a sexy Ruby one-liner?
还有一个建议:)
array.reject { |h| blacklist.any? { |b| h["email"].include? b } }
people.reject { |p| blacklist.include?("@" + p["email"].split("@", 2)[1]) }
Note that you should build the blacklist
as a set to make the inclussion test O(1).
require 'set'
blacklist = ["@test.com", "@gmail.com"].to_set
If this hash is coming from the DB, then you should do the filtering on the DB side.
If not, then don't run a separate reject
for each blacklist item. You probably want something like
array.reject {|rec| blacklist.include? "@#{rec['email'].split('@').last}" }
array = [{"email"=>"test@test.com", "name"=>"Test"},
{"email"=>"testA@gmail.com", "name"=>"Test A"},
{"name"=>"Test B", "email"=>"testB@test.com"},
{"email"=>"testC@yahoo.com", "name"=>"Test C"},
{"name"=>"Test D", "email"=>"testD@hotmail.com"},
{"email"=>"testE@test.com"},
{"name"=>"Test F", "email"=>"testF@test.com"}]
blacklist = ["test.com", "gmail.com"]
na = array.reject { |e| blacklist.include?(e["email"].split('@').last) }
=> [{"name"=>"Test C", "email"=>"testC@yahoo.com"}, {"name"=>"Test D", "email"=>"testD@hotmail.com"}]
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