I'm trying to figure out how to skip printing a row from a MySQL table if the variable is empty. For instance, I have a table full of information. I have a while loop that echos the result. How can I skip an entry if a variable is empty?
For instance, can I cancel the echo if 'tweet1' is empty in the row?
mysql_connect ($DBsever, $DBusername, $DBpass) or die ('I cannot connect to the database becasue: '.mysql_error());
mysql_select_db ("$DBname");
$query = mysql_query("SELECT * FROM $DBtable ORDER BY time");
while ($row = mysql_fetch_array($query)) {
echo "<br /><strong>".$row['time']." ".$row['headline']."</strong><br/>".$row['description']."<br />".$row['story1']." <a href=".$row['link1']." target='_blank'>".$row['link1']."</a> ".$row['tweet1']."<br />";}
You can use continue
control structure for skip an iteration. Please read the docs
Example:
if(!$row['tweet']) {
continue;
}
if (empty($row['tweet'])) {
continue;
}
你也可能不会在tweet1
没有信息的情况下返回行,这会使php检查tweet1中的数据变得不必要。
$query = mysql_query("SELECT * FROM $DBtable WHERE tweet1 IS NOT NULL ORDER BY time");
Try:
while ($row = mysql_fetch_array($query)) {
if ($row['tweet1'])
echo "<br /><strong>".$row['time']." ".$row['headline']."</strong><br/>".$row['description']."<br />".$row['story1']." <a href=".$row['link1']." target='_blank'>".$row['link1']."</a> ".$row['tweet1']."<br />";
}
while ($row = mysql_fetch_array($query)) {
if (!empty($row['tweet1']) {
echo "<br /><strong>".$row['time']." ".$row['headline']."</strong><br/>".$row['description']."<br />".$row['story1']." <a href=".$row['link1']." target='_blank'>".$row['link1']."</a> ".$row['tweet1']."<br />";
}
}
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