I wrote the following code while trying to learn threading in python.
import threading
import time
def printWorker(x,y):
t = time.time()
while time.time() - t < 10:
print "Name:%s Time:%s" %(y,str(time.time() - t))
time.sleep(x)
t1 = threading.Thread(target = printWorker(2,'Thread-1'))
t2 = threading.Thread(target = printWorker(3,'Thread-2'))
t1.start()
t2.start()
Im trying to get an output where both Thread-1 and Thread-2 start at same time. IE Print
Thread-1 Stuff, Thread-2 Stuff, Thread-1 Stuff, Thread-2 Stuff, instead of
Thread-1 Stuff, Thread-1 Stuff, Thread-1 Stuff, Thread-1 Stuff, Thread-2 Stuff, Thread-2 Stuff, Thread-2 Stuff, Thread-2 Stuff
Instead Thread-2 Only starts after Thread-1. I've checked online examples but I don't understand what I'm doing wrong mechanically.
To pass arguments you need to do this:
t1 = threading.Thread(target=printWorker, args=(2, 'Thread-1'))
t2 = threading.Thread(target=printWorker, args=(3, 'Thread-2'))
Your code is invoking printWorker on the main thread and starting two threads with target=None (the return value of printWorker).
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