I have a list of strings and some of them are equal. I need some script which would count equal strings. Ex:
I have a list with some words :
"House"
"Dream"
"Tree"
"Tree"
"House"
"Sky"
"House"
And the output should look like this:
"House" - 3
"Tree" - 2
"Dream" - 1
and so on
Use collections.Counter() . It is designed for exactly this use case:
>>> import collections
>>> seq = ["House", "Dream", "Tree", "Tree", "House", "Sky", "House"]
>>> for word, cnt in collections.Counter(seq).most_common():
print repr(word), '-', cnt
'House' - 3
'Tree' - 2
'Sky' - 1
'Dream' - 1
This is quite simple ( words
is a list of words you want to process):
result = {}
for word in set(words):
result[word] = words.count(word)
It does not require any additional modules.
For the following words
value:
words = ['House', 'Dream', 'Tree', 'Tree', 'House', 'Sky', 'House']
it will give you the following result:
>>> result
{'Dream': 1, 'House': 3, 'Sky': 1, 'Tree': 2}
Does it answer your question?
from collections import defaultdict
counts = defaultdict(int)
for s in strings:
counts[s] += 1
for (k, v) in counts.items():
print '"%s" - %d' % (k, v)
I will extend Tadeck's answer to print the results.
for word in set(words):
print '''"%s" - %d''' %(word, words.count(word))
Below code should get you as expected
stringvalues = ['House', 'Home', 'House', 'House', 'Home']
for str in stringvalues:
if( str in newdict ):
newdict[str] = newdict[str] + 1
else:
newdict[str] = 1
all = newdict.items()
for k,v in all:
print "%s-%s" % (k,v)
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