It seems like MySQL does not support characters with more than 3 bytes in its default UTF-8 charset.
So, in PHP, how can I get rid of all 4(-and-more)-byte characters in a string and replace them with something like by some other character?
NOTE: you should not just strip, but replace with replacement character U+FFFD to avoid unicode attacks, mostly XSS:
http://unicode.org/reports/tr36/#Deletion_of_Noncharacters
preg_replace('/[\x{10000}-\x{10FFFF}]/u', "\xEF\xBF\xBD", $value);
Since 4-byte UTF-8 sequences always start with the bytes 0xF0-0xF7
, the following should work:
$str = preg_replace('/[\xF0-\xF7].../s', '', $str);
Alternatively, you could use preg_replace
in UTF-8 mode but this will probably be slower:
$str = preg_replace('/[\x{10000}-\x{10FFFF}]/u', '', $str);
This works because 4-byte UTF-8 sequences are used for code points in the supplementary Unicode planes starting from 0x10000
.
Here's an example:
<?php
mb_internal_encoding("UTF-8");
//utf8 string, 13 bytes, 9 utf8 chars, 7 ASCII, 1 in latin1, 1 outside the BMP
$str = "qué \xF0\x9D\x92\xB3 tal";
$array = mbStringToArray($str);
print "str: [$str] strlen:" . strlen($str) . " chars:" . count($array) . "\n";
$str1 = "";
foreach($array as $c) {
// print "$c : " . strlen($c) ."\n";
$str1 .= strlen($c)<=3? $c : '?';
}
print "[$str1]\n";
function mbStringToArray ($str) {
if (empty($str)) return false;
$len = mb_strlen($str);
$array = array();
for ($i = 0; $i < $len; $i++) {
$array[] = mb_substr($str, $i, 1);
}
return $array;
}
Or, a little more compact and efficient:
<?php ///
mb_internal_encoding("UTF-8");
//utf8 string, 13 bytes, 9 utf8 chars, 7 ASCII, 1 in latin1, 1 outside the BMP
$str = "qué \xF0\x9D\x92\xB3 tal";
$str1 = trimOutsideBMP($str);
print "original: [$str]\n";
print "trimmed: [$str1]\n";
// Replaces non-BMP characters in the UTF-8 string by a '?' character
// Assumes UTF-8 default encoding ( if not sure, call first mb_internal_encoding("UTF-8"); )
function trimOutsideBMP($str) {
if (empty($str)) return $str;
$len = mb_strlen($str);
$str1 = '';
for ($i = 0; $i < $len; $i++) {
$c = mb_substr($str, $i, 1);
$str1 .= strlen($c) <= 3 ? $c : '?';
}
return $str1;
}
Came across this question when trying to solve my own issue (Facebook spits out certain emoticons as 4-byte characters, Amazon Mechanical Turk does not accept 4-byte characters).
I ended up using this, doesn't require mbstring extension:
function remove_4_byte($string) {
$char_array = preg_split('/(?<!^)(?!$)/u', $string );
for($x=0;$x<sizeof($char_array);$x++) {
if(strlen($char_array[$x])>3) {
$char_array[$x] = "";
}
}
return implode($char_array, "");
}
Below function change 3 and 4 bytes characters from utf8 string to '#':
function remove3and4bytesCharFromUtf8Str($str) {
return preg_replace('/([\xF0-\xF7]...)|([\xE0-\xEF]..)/s', '#', $str);
}
Here is my implementation to filter out 4-byte chars
$string = preg_replace_callback(
'/./u',
function (array $match) {
return strlen($match[0]) >= 4 ? null : $match[0];
},
$string
);
you could tweak it and replace null
(which removes the char) with some substitute string. You can also replace >= 4
with some other byte-length check.
Another filter implementation, more complex.
It try transliterate to ASCII characters, otherwise iserts unicode replacement character to avoid XSS, eg.: <a href='java\script:alert("XSS")'>
$tr = preg_replace_callback('/([\x{10000}-\x{10FFFF}])/u', function($m){
$c = iconv('ISO-8859-2', 'UTF-8',iconv('utf-8','ISO-8859-2//TRANSLIT//IGNORE', $m[1]));
if($c == '')
return '�';
return $c;
}, $s);
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