JavaScript Random Positive or Negative Number

Question

I need to create a random -1 or 1 to multiply an already existing number by. Issue is my current random function generates a -1, 0, or 1. What is the most efficient way of doing this?

Answer 1

Don't use your existing function - just call Math.random() . If < 0.5 then -1, else 1:

var plusOrMinus = Math.random() < 0.5 ? -1 : 1;

Answer 2

I've always been a fan of

Math.round(Math.random()) * 2 - 1

as it just sort of makes sense.

• Math.round(Math.random()) will give you 0 or 1

• Multiplying the result by 2 will give you 0 or 2

• And then subtracting 1 gives you -1 or 1.

Intuitive!

Answer 3

why dont you try:

(Math.random() - 0.5) * 2

50% chance of having a negative value with the added benefit of still having a random number generated.

Or if really need a -1/1:

Math.ceil((Math.random() - 0.5) * 2) < 1 ? -1 : 1;

Answer 4

Just for the fun of it:

var plusOrMinus = [-1,1][Math.random()*2|0];  

or

var plusOrMinus = Math.random()*2|0 || -1;

But use what you think will be maintainable.

Answer 5

There are really lots of ways to do it as previous answers show.

The fastest being combination of Math.round() and Math.random:

// random_sign = -1 + 2 x (0 or 1); 
random_sign = -1 + Math.round(Math.random()) * 2;   

You can also use Math.cos() ( which is also fast ):

// cos(0) = 1
// cos(PI) = -1
// random_sign = cos( PI x ( 0 or 1 ) );
random_sign = Math.cos( Math.PI * Math.round( Math.random() ) );

Answer 6

我正在使用underscore.js 随机播放

var plusOrMinus = _.shuffle([-1, 1])[0];

Answer 7

多年以后，让我说一下显而易见的；

Math.sign(Math.random()-0.5);

Answer 8

Math.random() - Math.random()或Math.random() * (Math.random() > 0.5 ? 1 : -1 )给你