I need a regex that would match a positive and negative decimal value, empty string ('') and also minus only ('-'). Since I need it inside the function that handles the change of a numeric field and in order to add a negative value the user firstly adds the "-" or deletes the old value (""), I need to match all these 3 conditions.
So, to sum up, the regex should allow:
What I have until now is:
function sanitizeInputValue(value: string) {
var re = new RegExp('^$|^-?\\d{1,9}(\\.\\d{1,2})?$');
return value.match(re) === null ? 0 : value;
}
Use javascript's built in Number
to convert the string into a numeric value right before you return from the function.
Also, I modified your regex so that it can accept input like .23
and 0.2345
.
function sanitizeInputValue(value) { var re = new RegExp('^$|^-?(\\d+)?(\\.?\\d*)?$'); return value.match(re) === null? 0: Number(value); } console.log(sanitizeInputValue("-23")); // -23 console.log(sanitizeInputValue("42.123")); // 42.123 console.log(sanitizeInputValue("-.34")); // -0.34 console.log(sanitizeInputValue("")); // 0 console.log(sanitizeInputValue("-8.")); // -8 console.log(sanitizeInputValue("-8.4")); // -8.4
You can make matching the digits with decimal parts optional so you would also match the hyphen only ^$|^-?(?:\d{1,9}(\.\d{1,2})?)?$
As then all parts are optional, you can omit the ^$
and then all parts are optional.
^-?(?:\d{1,9}(?:\.\d{1,2})?)?$
Explanation
^
Start of string -?
Optional hyphen(?:
Non capture group
\d{1,9}
match 1-9 times a digit (?:\.\d{1,2})?
Optionally match a dot and 1-2 digits)?
Close non capture group and make it optional as well$
End of string. var re = new RegExp("^-?(?:\\d{1,9}(?:\\.\\d{1,2})?)?$"); [ "", "-", "1", "1.2", "test", "1234567890", "1.123", "-2", "-2.6" ].forEach(s => console.log(s + " --> " + re.test(s)));
Edit
As you also want to match -8.
and don't want to limit the amount of digits, you could use:
^-?(?:\d+\.?\d*)?$
Explanation
^
Start of string -?
Optional -
(?:
Non capture group
\d+\.?\d*
Match 1+ digits, optional dot and 0+ digits )?
Close group and make it optional$
End of string var re = new RegExp("^-?(?:\\d+\\.?\\d*)?$"); [ "-8.", "", "-", "1", "1.2", "test", "1234567890", "1.123", "-2", "-2.6" ].forEach(s => console.log(s + " --> " + re.test(s)) );
function sanitizeInputValue(value) {
var re = /^$|\-?[0-9]\d*(\.\d*)?|-/;
return value.match(re) ? value : 0;
}
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