how to sort XML file using java

Question

I have an xml file and want to sort like this in txt file

Soccer | England | Premier League | Blackpool FC - Birmingham City 5-1

 <?xml version="1.0" encoding="UTF-8"?> <LivescoreData> <Sport SportId="1"> <Name language="en">Soccer</Name> <Name language="se">Fotboll</Name> <Category CategoryId="34"> <Name language="en">Australia</Name> <Name language="se">Australien</Name> <Tournament TournamentId="144"> <Name language="en">Hyundai A-League</Name> <Name language="se">Hyundai A-League</Name> <Match MatchId="4616735"> .... etc 

Answer 1

Use dom4j .It's a great library for working with xml files.
You can download it from here .

    SAXReader reader = new SAXReader();
    Document doc = reader.read(new File("myXML.xml"));
    Element content = doc.getRootElement();
    List<Element> myNeededElements = content.elements("neededElementName");

After this you'll have all elements with the name you want (say "neededElementName") in myNeededElements list.

Answer 2

If you have flexible options in selecting a library/framework, one of the solutions is to use XStream and deserialize the xml into a collection of java objects and sort 'em.

For Ex:

List<Employee> employeeList = xStream.fromXML(xmlFile);
Collections.sort(employeeList, new Comparator() { .... });

EDIT : Also check the below links:

1) How to sort XML elements in Java?

2) XSLT Sort

Answer 3

Sorting an XML file can generally be done in a few lines of XSLT or XQuery, and invoking XSLT or XQuery only takes a few lines of Java. However, it's totally unclear from your post what your desired input and output are (or at any rate, what relationship they have to each other.)