If there is an error function mysql_result then it returns 0?
I looked everywhere but i could not find an answer ....
<?php
include "config.php";
$result = mysql_query("SELECT `price` FROM `prices` where bin = 1 limit 0,10" ) ;
$i=0;
$d=0;
while($i!=10){
$d=$d+mysql_result($result, $i)or die($d);
$i++;
}
?>
its returns 7 errors ...
( ! ) Warning: mysql_result() [function.mysql-result]: Unable to jump to row 3 on MySQL result index 5 in C:\\wamp\\www\\fom\\Untitled 1.php on line 7
Try this:
<?php
include "config.php";
$result = mysql_query("SELECT `price` FROM `prices` where bin = 1 limit 0,10" ) ;
$i=0;
$rows = mysql_num_rows($result);
$d=0;
while($i < $rows && $tmp=mysql_result($result, $i++)){
$d+=$tmp;
}
?>
In my opinion, you shouldn't use mysql_result. It is slower than the other methods.
Try mysql_fetch_array()
prototype:
while ($row =
mysql_fetch_array ($result)){
echo (whatever you want depending upon the index);
}
or you can also return it as an array.
尝试删除第7行的die($ d)并再次检查。
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