简体   繁体   中英

Validate an XML against an XSD in Java / Getting a hold of the schemaLocation

How can one validate an XML file using an XSD in Java? We don't know the schema in advance. I would like to be able to get the schemaLocation , download the XSD, cache it and then perform the actual validation.

The problem is, that with javax.xml.parsers.DocumentBuilder / DocumentBuilderFactory classes I can't seem to be able to get a hold of the schemaLocation in advance. What's the trick for this? Which classes should I look into?

Perhaps there's a more suitable API I can use? The whole problem is that we need to validate dynamically, without (necessarily) having the XSDs locally.

How could one get a hold of the URL of schemaLocation defined in the XSD file?

I know you can set features/attributes, but that's a different thing. I need to get the schemaLocation from the XSD first.

Please advise!

Given that you are using Xerces (or JDK default), have you tried setting this feature to true on the factory: http://apache.org/xml/features/validation/schema . There are other features that you can play with regarding schemas: http://xerces.apache.org/xerces2-j/features.html

UPDATE 2 (for caching):

Implement a org.w3c.dom.ls.LSResourceResolver and set this on the SchemaFactory using the setResourceResolver method. This resolver would either get the schema from cache or fetch it from wherever the location refers to.

UPDATE 3:

LSResourceresolver example (which I think will be a good starting point for you):

/**
 * Resolves resources from a base URL
 */
public class URLBasedResourceResolver implements LSResourceResolver {

private static final Logger log = LoggerFactory
        .getLogger(URLBasedResourceResolver.class);

private final URI base;

private final Map<URI, String> nsmap;

public URLBasedResourceResolver(URL base, Map<URI, String> nsmap)
        throws URISyntaxException {
    super();
    this.base = base.toURI();
    this.nsmap = nsmap;
}

@Override
public LSInput resolveResource(String type, String namespaceURI,
        String publicId, String systemId, String baseURI) {
    if (log.isDebugEnabled()) {
        String msg = String
                .format("Resolve: type=%s, ns=%s, publicId=%s, systemId=%s, baseUri=%s.",
                        type, namespaceURI, publicId, systemId, baseURI);
        log.debug(msg);
    }
    if (type.equals(XMLConstants.W3C_XML_SCHEMA_NS_URI)) {
        if (namespaceURI != null) {
            try {
                URI ns = new URI(namespaceURI);
                if (nsmap.containsKey(ns))
                    return new MyLSInput(base.resolve(nsmap.get(ns)));
            } catch (URISyntaxException e) {
                // ok
            }
        }
    }
    return null;
}

}

The implementation of MyLSInput is really boring:

class MyLSInput implements LSInput {

private final URI url;

public MyLSInput(URI url) {
    super();
    this.url = url;
}

@Override
public Reader getCharacterStream() {
    return null;
}

@Override
public void setCharacterStream(Reader characterStream) {

}

@Override
public InputStream getByteStream() {
    return null;
}

@Override
public void setByteStream(InputStream byteStream) {

}

@Override
public String getStringData() {
    return null;
}

@Override
public void setStringData(String stringData) {

}

@Override
public String getSystemId() {
    return url.toASCIIString();
}

@Override
public void setSystemId(String systemId) {
}

@Override
public String getPublicId() {
    return null;
}

@Override
public void setPublicId(String publicId) {
}

@Override
public String getBaseURI() {
    return null;
}

@Override
public void setBaseURI(String baseURI) {

}

@Override
public String getEncoding() {
    return null;
}

@Override
public void setEncoding(String encoding) {

}

@Override
public boolean getCertifiedText() {
    return false;
}

@Override
public void setCertifiedText(boolean certifiedText) {

}

}

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM