简体   繁体   中英

NEW to PHP… Need Help… Regarding nested functions

i'm playing around and trying to incorporate a nested function into my login script. The functions are all below. Also, beneath my functions is the portion of the login script im trying to incorporate them in. However, everytime I try to log in, it says invalid username. However if I user function a and b in the login script instead of function d, everything works fine. Can some tell me where i',m going wrong? Thanks.

//a -username

function username_check($username){

$usercheck = "SELECT user_id FROM users WHERE username ='$username'";
$userqry = mysql_query($usercheck) or die ("Could not match data because ".mysql_error());
$num_rows = mysql_num_rows($userqry);
return ($num_rows == 1) ? true : false;
}

//b - password

function password_check($password, $username){

$passwordcheck = "SELECT password FROM users WHERE username ='$username'"; 
$passwordqry = mysql_query($passwordcheck) or die ("Could not match data because ".mysql_error());

while($retrievepassword = mysql_fetch_array($passwordqry))  

{

 $password = md5($password);

 return ($password != $retrievepassword['password']) ? true : false;

 }
 }
 //c    -email

 function email_check($email){

 $emailcheck = "SELECT user_id FROM users WHERE email = '$email'"; 
 $emailqry = mysql_query($emailcheck) or die ("Could not match data because ".mysql_error());
 $num_rows = mysql_num_rows($emailqry); 

 return ($num_rows == 1) ? true : false;
 }

 //d -username + password + email check? all in one? DOESNT WORK

 function user_check($username = NULL, $password = NULL, $email = NULL) {

 if(($email !=NULL)) {
 email_check($email);
 }

 elseif(($username !=NULL) && ($password!=NULL)){
 password_check($password,$username);   
 }

 elseif(($username !=NULL) ) {
 username_check($username);
 }

 }


 //LOGIN SCRIPT

 if (user_check($username1) ==false) { 
    $logerrors[] = 'Invalid username';

 }
 elseif (user_check($password1, $username1)) { 
    $logerrors[] = 'Incorrect password';`

很好,函数d不返回任何值。

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM