I have this regex variable:
var regexp = new RegExp(RegExp.quote(myExpression) + '\\b', 'g');
which searches for expression that has a space after it. (RegExp.quate() I got from this How to escape regular expression in javascript? )
I want to search for it only outside curly brackets .
so if I myExpression = "cat"
and I have this string:
the cat { is cat { and } cat {and { another cat } } and cat } and another cat
^^^ ^^^
I want to get a match only for the first cat and the last cat - I don't want any match for anything inside the outer curly brackets.
I found some regex for this but non of them worked as I hoped for.
what do I need to write to get it done?
thanks, Alon
Something like this problem of matching nested brackets is not possible to solve using a single regex. Here is my take to resolve your problem:
var myExpression = "cat";
var s = 'the cat {is cat { and} cat {and { another cat}}and cat } and another cat';
arr = s.split(/(?=(?:\b|\W))\s*/g);
document.writeln("<pre>split: " + arr + "</pre>");
//prints: the,cat,{,is,cat,{,and,},cat,{,and,{,another,cat,},},and,cat,},and,another,cat
var level=0;
for (i=0; i<arr.length; i++) {
if (level == 0 && arr[i] == myExpression)
document.writeln("<pre>Matched: " + arr[i] + "</pre>");
if (arr[i] == "{")
level++;
else if (arr[i] == "}")
level--;
}
一种策略是用空字符串查找/替换所有{。*} ...然后查找所有猫?
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