SQL SERVER 2008 R2 find column words in another column

Question

I have a table looks like:

AV          AVE
AVENUE      AVE
AVEAPT      AVE
APT         #

First word to be found and replaced by second word.

I have to find these words in Address field in another table and replace all these?

What is the best way to do it?

Answer 1

UPDATE a
SET Address = REPLACE(Address, r.Word, r.Replacement)
FROM AddressTable AS a
JOIN ReplaceTable AS r
ON a.Address LIKE '%' + r.Word + '%'