Select rows where count of grouped data =2

Question

I have to get the users, which appear at least two weeks before and after the given date. So lets say I have data:

 userName    date  week 
 user1  27 10 2011  44
 user1  27 10 2011  44 
 user1  27 10 2011  44 
 user2  21 04 2011  17 
 user2  29 04 2011  17 
 user2  02 05 2011  19 
 user2  03 05 2011  19 
 user2  16 05 2011  21
 user2  23 05 2011  22 
 user3  06 01 2011  24 
 user3  14 05 2011  25 
 user3  20 05 2011  26 
 user3  27 05 2011  27

and I need to get the results first grouped by user and week, then I need to count how many weeks the user appears before (lets say week 20) and after, and then select only ones who appears at least 2 weeks before and after, so in my case I would get the result

user2 

Unfortunately I cannot create viewTable because of the database restrictions. this query is giving me only the first part of the results, data grouped by user and week, but I have no idea how to count grouped data:

SELECT   username, 
         min(a.actionDate) as date, 
         datepart(wk,a.actionDate) as week 
FROM     Table1 a           
GROUP BY username , 
         datepart(wk,amd.actionDate) 

thanks for any help.

Answer 1

To return users which have date records at least two weeks before and two weeks after a specified date, try:

select username
from Table1
group by username
having datediff(wk, min(actiondate), @date) >= 2 and 
       datediff(wk, @date, max(actiondate)) >= 2