Problems passing data to PHP from jQuery's AJAX

Question

im trying to pass an array of data to a PHP script using Jquery's AJAX; this is my JS:

var dataObject = {
    shippingDataRow: [{
        name: $('#shippingData_name').val(),
        street: $('#shippingData_street').val(),
        number: $('#shippingData_number').val(), 
    }]

};

$.ajax({
    type: "post",
    data: { action: 'test', data: dataObject },
    cache: false,
    url: "php/post_test.php",  
});

And this is the PHP (just doing some tests, before I can write all procedures),

<?php
    function test(){
        $dataObject = $_POST['dataObject'];
        print_r( $dataObject );
    }
?>

In Chrome's Developer Tools, I can see the Status Code:200 OK; even all the array with the correct values, but when I open the php it doesn't work.

Any ideas?

Answer 1

try: $dataObject = $_POST['data'];

You need to refer to the key of the posted data, not the value in javascript.

Answer 2

Change:

$dataObject = $_POST['dataObject'];

To:

$dataObject = $_POST['data'];

Answer 3

您的帖子应该是

$_POST['data'];

Answer 4

您没有在任何地方调用test（）。so，它的提示返回200ok但响应为null。在test_php中回显任何内容并检查。

Answer 5

var dataObject = {
    shippingDataRow: {
        name: $('#shippingData_name').val(),
        street: $('#shippingData_street').val(),
        number: $('#shippingData_number').val()
    }
};

$.ajax({
    type: "post",
    data: { action: 'test', data: dataObject },
    cache: false,
    url: "php/post_test.php"
});

-

<?php
   $dataObject = $_POST['data'];
   print_r( $dataObject );
?>

Answer 6

As others mentioned, $_POST['data'] will get you the data array.

Also, using $_REQUEST works well as it'll target both get/post requests.