What's the regular expression for positive whole numbers only? (zero is not allowed)
I was able to get the regular expression for numbers only which is ^\\d+$
. I've been trying to look for one online but it's already been an hour so I've decided to post it here on Stack Overflow.
matches:
1 || 2 || 444 || 9000 || 012
non-matches:
9.2 || -90
^0*[1-9]\\d*$
将匹配除零之外的所有数字。
May be you are looking for ^[1-9]+$
pattern. It'll match 1245
, 2253
etc. But not 1003
. or 0124
. If you want to match the 3rd number ( 1003
) as well use ^[1-9]\\d*$
pattern.
In php you'd use
preg_match('/^[1-9]\d*$/', $subject, $matches)
This is obviously:
[1-9]\d*
(one to nine followed by zero or more digits.) This would exclude things like 0190, of course.
I know you asked for a regex, but you might consider
$opts = array(
'options' => array(
'min_range' => 1,
'max_range' => PHP_INT_MAX
)
);
$n = filter_var($input, FILTER_VALIDATE_INT, $opts);
/^\+?([1-9]|0.)[0-9\.]*$/
this pattern may help you, but i think you must your programming language skills to do arithmetic check. for example in php . " $is_positive = $input > 0
" yes it is so easy :)
尝试这个
[1-9]\d*|[0]*[1-9]\d*
这是允许0到100而不是01的一个
^((([0]$)|[1-9][0-9]{0,1})|100)$
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