C++: Is it safe to compare a 64bit integer with a 32bit integer?
Question
Assuming I have 2 variables:
uint64_t a = ...
uint32_t b = ...
Will comparing the integers yield the expected results, ie (a != b) , or (b > a) ?
2 answers
solution1
22 ACCPTED 2012-04-11 20:14:20
No problem. The compiler promotes the 32-bit to 64-bit before the comparison
solution2
8 2012-04-11 20:14:39
Short answer - yes. The 'smaller' is converted to bigger one before comparison.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.
Related Question
extract 32bit from 64bit integer
What happens exactly when a 32bit integer overflows on a 64bit machine?
How does 64bit integer type guarantee atomicity on 32bit operation system?
Can the optimizer elide assignment from 64bit to 32bit integer types?
How to have both 32bit and 64bit float in C++
access 64bit dll from 32bit process using C++
C++ 32bit vs 64bit floating limit
Linking both 32bit and 64bit .so files with g++ for a c++ program
Reading 64bit registry from 32bit c++ program?
What is Compatible “int” type in both 32Bit & 64Bit windows in C++?
Related Tags