I have a web page with a jQuery lightbox that opens automatically on page load. In the lightbox I have implemented the Facebook Like button (this is a 2 click solution for Facebook Like button in email). Now, when a Facebook user visits my web page by clicking on the "Liked" URL on Facebook I want to turn off the lightbox. I don't want to have to create two different pages (one with lightbox turned on and another turned off) and I think I can avoid this by adding a parameter to the URL with Javascript then turn the lightbox on/off based on that parameter. Is this a safe way to do this? How would I do this?
You can get URL params with this JS function that I found here :
function getUrlVars() {
var vars = {};
var parts = window.location.href.replace(/[?&]+([^=&]+)=([^&]*)/gi, function(m,key,value) {
vars[key] = value;
});
return vars;
}
Then *add use ?lightbox=1
eg www.example.com?lightbox=1
and read it with the above function:
if(getUrlVars()["lightbox"]=="1"){
//...
}
*to add parameters you can either:
element.href = "http://www.newURL.com?param=1";
and wait for the user to click them window.location.href = "http://www.newURL.com?param=1";
I believe this is the rough code you're after:
<script type="text/javascript">
document.location="http://example.com/index.php?noLightBox=1";
</script>
Then on index.php, you'd want something such as:
<?php
function isset_or(&$check, $alternate = NULL)
{
return (isset($check)) ? (empty($check) ? $alternate : $check) : $alternate;
}
function getGETPOST($var)
{
return isset_or($_GET[$var],isset_or($_POST[$var],"Empty"));
}
?>
Example:
if(getGETPOST('noLightBox') != 1) {
// Code to display the light box comes here.
}
// Else normal page code
Hope this was helpful! Source: http://php.net/manual/en/function.isset.php & W3School's tutorials on PHP
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