I have the following function:
std::vector<double>residuals;
std::cout << Print_res(std::cout);
std::ostream& Print_res(std::ostream& os) const {
os << "\tresidual" << std::endl;
for (unsigned int i = 0 ; i < 22 ; i++) {
os << "\t\t" << residuals[i] << std::endl;
}
os << std::flush;
return os;
};
It prints the residuals correctly, but at the end of the output tags an address as follows:
2275
2279.08
2224.0835
0x80c5604
how do I fix this? EDIT: after reading everyone's comments I replaced the call to the function Print_res
with a std::copy
as
std::copy(residuals.begin(), residuals.end(), std::ostream_iterator<double>(std::cout,"\n"));
and that did not print the address, so I presume there is something wrong in the way I have written the function.
std::cout << Print_res(std::cout);
This is not legal at global scope so the code that you have posted is not valid. If this statement were executed from, say, a function then Print_res
would be called and then the return value of Print_res
would also be streamed to std::cout
. This is most likely not what you meant. You probably want just this:
Print_res(std::cout);
Your statement performs the equivalent of:
std::cout << std::cout;
In C++03 (which you must be using), std::cout
has an operator void*
(from std::basic_ios<char>
) the result of which is what is being printed.
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